In an ap the 24th term is twice the 10th term
WebIN A CERTAIN A.P. THE 24th TERM IS TWICE THE 10th TERM . PROVE THAT 72nd TERM IS TWICE THE 34 th TERM. Posted by: JUHI GUPTA in Algebra 1 decade ago, Total Answer(s): 2. Answer(s) Let the first term and the common difference be "a" and "d" Given. T 24 = 2 T 10. or, a + 23d = 2(a + 9d) WebMar 31, 2024 · term of an AP as ( a 1 + 23 d) Now, it is given that, the 24 t h term is twice the 10 t h term, thus we get; ∴ a 24 = 2 × a 10 ∴ a 1 + 23 d = 2 × ( a 1 + 9 d) From (i) and (ii) a 1 …
In an ap the 24th term is twice the 10th term
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WebSolution Here, we are given that 24 th term is twice the 10 th term, for a certain A.P. Here, let us take the first term of the A.P. as a and the common difference as d We have to prove that a 72 = 2 a 34 So, let us first find the two terms. As we know a n = a + ( n - 1) d For 10th term (n = 10) a 10 = a + ( 10 - 1) d = a + 9d Web24 The 10 th term from the end in the AP 5 8 11 is 95 then the number of terms. 24 the 10 th term from the end in the ap 5 8 11 is 95. School University of Delhi; Course Title PHYSICS 573; Uploaded By SuperValor10801. Pages 16 This preview shows page 13 - …
WebJun 14, 2024 · Solution: Given that, 24th term is twice the 10th term. As we know that, to find nth term in an A.P = a + (n – 1)d a 24 = 2 (a10) a + (24 – 1)d = 2 (a + (10 – 1)d) a + 23d = 2 (a + 9d) a + 23d = 2a + 18d a = 5d …. (1) Now, the 72nd term can be expressed as: a 72 = a + (72 – 1)d = a + 71d = a + 5d + 66d = a + a + 66d [using (1)] = 2 (a + 33d) WebThe 24 th term of an A.P. is twice its 10 th term. Show that its 72 nd term is 4 times its 15 th term. Advertisement Remove all ads Solution Let a be the first term and d be the common difference. We know that, nth term = an = a + ( n − 1) d According to the question, a24 = 2 a10 ⇒ a + (24 − 1) d = 2 ( a + (10 − 1) d) ⇒ a + 23 d = 2 a + 18 d
WebMar 31, 2024 · term of an AP as ( a 1 + 23 d) Now, it is given that, the 24 t h term is twice the 10 t h term, thus we get; ∴ a 24 = 2 × a 10 ∴ a 1 + 23 d = 2 × ( a 1 + 9 d) From (i) and (ii) a 1 + 23 d = 2 a 1 + 18 d ∴ 2 a 1 − a 1 = 23 d − 18 d ∴ a 1 = 5 d - (iii) Therefore 1 s t term of AP is 5 times the common difference. Now, 34 t h term is:- WebInformation about If 24th term of an Ap is twice the 10th term, then prove that 72th term is equal to 4 times of its 15th term. covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If 24th term of an Ap is twice the 10th term, then prove that 72th ...
WebIf 10 times the 10 th term of an A.P. is equal to 15 times the 15 th term, show that 25th term of the A.P. is zero. Hard Solution Verified by Toppr We know that the n th term of the arithmetic progression is given by a+(n−1)d Given that the 10 times the 10 th term is equal to 15 times the 15 th term Therefore, 10(10 thterm)=15(15 thterm) high voltage electric 6WebOct 26, 2016 · In an A.P, 24th term is twice the 10th term.prove that the 36th term is twice the 16th term. Advertisement Expert-Verified Answer 185 people found it helpful Golda … how many episodes of clannadWebFuture of mathematics cbse saharsaPlease subscribe and share and like our channel for more videosSUDHIR SIR saharsaA lot of thanks for your support high voltage electric motorWeb20 hours ago · INGLEWOOD, Calif. (AP) — Jason Kelce has excelled as one of the NFL’s best offensive linemen for his ability to quickly adjust blocking schemes and make split-second decisions to ensure his ... high voltage emmetsburg twitterWebNov 23, 2024 · Given that 24th term (t24) is twice the 10th term (t10). a + 23d = 2 (a + 9d) a + 23d = 2a + 18d a = 5d ------ (1) Given that 72nd term (t72) is twice the 34th term. a + 71d = 2 (a + 33d) a + 71d = 2a + 66d a = 5d ---- (2) From (1) and (2), LHS = RHS. Hope this helps! Find Math textbook solutions? Class 9 Class 8 Class 7 Class 6 Class 5 Class 4 high voltage emi filterWebMay 30, 2024 · Answer: Given : 24th term (a24) is twice the 10th term a24 = 2a10 a + (24 - 1) d = 2 (a + (10 - 1)d [an = a + (n – 1) d] a + 23d = 2 (a + 9d) a + 23d = 2a + 18d a - 2a = 18d - 23d -a = - 5d a = 5d ………….. (1) We have to prove that, 72th term is twice its 34 term a72 = 2a34 a + (72 -1)d = 2 (a + (34 - 1)d a + 71d = 2 (a + 33d) 5d + 71d = 2 (5d + 33d) how many episodes of claws in final seasonWebApr 28, 2024 · In a certain AP 24th term is twice the 10th term.Prove that 72nd term is twice the 34th term See answers Advertisement Swarup1998 Proof : Let, the first term of the AP is a and the common difference is d. Then, n-th term = a + (n - 1)d • 24th term = a + (24 - 1)d = a + 23d • 10th term = a + (10 - 1)d = a + 9d • 72nd term = a + (72 - 1)d = a + 71d how many episodes of clarice